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1. To measure voltage, the selector on the DMM must be turned to
a. Any position; the meter automatically adjusts
b. The "V" position
c. The "A" position
d. The "Ω" position
b. The "V" position
2. To measure the battery voltage, place the DMM probes
a. At H and C
b. At B and G
c. At B and E
d. At D and F
d. At D and F
3. With the switch closed, the voltage between points G and F will measure about
a. The same as the battery voltage
b. Half the battery voltage
c. Zero
d. Battery voltage divided by resistor's resistance
c. Zero
4. A DMM voltage reading of "9.48 mV" is equivalent to
a. 0.00948 V
b. 0.948 V
c. 0.849 V
d. 948 kV
a. 0.00948 V
5. While measuring the voltage drop across the resistor
a. The battery polarity must be reversed.
b. The DMM probes must be connected at C and D.
c. The DMM knob must be set on A.
d. The switch must be closed.
d. The switch must be closed.
6. To measure current, the selector on the DMM must be turned to
a. The "A" position
b. The W position
c. Any position; the meter automatically adjusts.
d. The "V" position
a. The "A" position
7. To find the current through the resistor, set the selector for measuring current,
a. Close the switch, and place the DMM probes at B and C.
b. Open the switch, and place the DMM probes at D and E.
c. Open the switch, and place the DMM probes at G and F.
d. Close the switch, and place the DMM probes at B and G.
c. Open the switch, and place the DMM probes at G and F.
8. One way to find the resistance of the resistor, is to apply Ohm’s Law by
a. Closing the switch, and measuring the current with probes at D and E, and the voltage with probes at B and C.
b. Opening the switch, and measuring the current with probes at F and G, and then closing the switch and measuring the voltage with probes at B and C.
c. Closing the switch, and measuring the current with probes at B and G, and then opening the switch and measuring the voltage with probes at D and E.
d. Opening the switch, and measuring the current with probes at D and E, and the voltage with probes at F and G.
b. Opening the switch, and measuring the current with probes at F and G, and then closing the switch and measuring the voltage with probes at B and C.
9. Suppose you measure the voltage with the red probe on the "+" battery terminal and black probe on the "–" terminal. If you reverse the red and black probes,
a. It doesn’t matter—you’ll see the same voltage reading both times.
b. The voltage will read zero when you reverse the probes.
c. The value in the display will be the same, but with a different sign (positive or negative).
d. The reading in the display in the second case will be the reciprocal of the first reading.
c. The value in the display will be the same, but with a different sign (positive or negative).
10. With DMM selector knob turned to W, you can measure the resistor by
a. Opening the switch and placing the probes at C and H.
b. Closing the switch and placing the probes at C and G.
c. Closing the switch and placing the probes at B and C.
d. Opening the switch and placing the probes at F and G.
a. Opening the switch and placing the probes at C and H.
11. The switch labeled "Channel" has three settings: A, B, and A & B. This switch set to "A" would be appropriate when
a. The Source switch is set to "EXT."
b. You want Channel A to appear on the top of the screen, and Channel B on the bottom.
c. You want to watch television channel A.
d. You wish to study the signal from the cable plugged into the CH A jack.
d. You wish to study the signal from the cable plugged into the CH A jack.
12. Which of the following is usually the first step in measuring the amplitude of an input signal?
a. Set the TRIGGER to a Positive slope.
b. Turn the X-Position and Y-Position fully counterclockwise.
c. Turn the TIME/DIV knob until the trace is visible on the screen.
d. Turn ON the oscilloscope.
d. Turn ON the oscilloscope.
13. The VOLTS/DIV knob is used to
a. Calibrate the voltage sensitivity of the oscilloscope.
b. Make the wave from peak-to-peak fit in the display.
c. Move the curve on the display up or down.
d. Move the curve on the display left or right.
b. Make the wave from peak-to-peak fit in the display.
14. The TIME/DIV knob is used to
a. Make between one and two cycles of the wave visible in the display.
b. Compensate for a positive or negative trigger setting.
c. Adjust the display to measure the peak-to-peak value.
d. Adjust the frequency of the input signal.
a. Make between one and two cycles of the wave visible in the display.
15. Which of the following knobs would you use to adjust the display to better determine the peak-to-peak amplitude?
a. Level
b. Y-POS
c. CHANNEL
d. Source
b. Y-POS
16. After adjusting the display, you count 5½ grid squares from the bottom of the wave to the top of the wave. The TIME/DIV setting is "0.2 ms," and the VOLTS/DIV setting is 50 mV. The peak-to-peak amplitude of this signal is
a. 275 mV
b. 5.5 mV
c. 10 mV
d. 1.1 mV
a. 275 mV
17. Seeing the signal shown in the illustration, which of the following adjustments would improve the display to better measure the amplitude of the signal?
a. Adjusting the Level knob to more negative.
b. Turning the VOLTS/DIV knob clockwise.
c. Turning the TIME/DIV knob counter-clockwise.
d. Sliding CHANNEL switch to the A position.
b. Turning the VOLTS/DIV knob clockwise.
18. After adjusting the display, you count 9.2 grid squares between two consecutive peaks of the wave (left to right). The TIME/DIV setting is "10 ms," and the VOLTS/DIV setting is 20 V. The period of this signal is
a. 10.8 sec
b. 0.102 sec
c. 0.092 sec
d. 184 sec
c. 0.092 sec
19. The signal described in the previous question has a frequency of
a. 10.8 Hz
b. 5.4 kHz
c. 9.2 mHz
d. 102 MHz
a. 10.8 Hz
20. A signal with a very high frequency would require you to
a. Turn the TIME/DIV knob far clockwise.
b. Turn the X-POS and Y-POS knobs almost all the way counter-clockwise.
c. Change to Channel A.
d. Adjust the VOLTS/DIV so the peak-to-peak amplitude fits within one grid square.
a. Turn the TIME/DIV knob far clockwise.